|
Main Forum Page
|
The Gyroscope Forum |
23 November 2024 14:52
|
|
Welcome to the gyroscope forum. If you have a question about gyroscopes in general,
want to know how they work, or what they can be used for then you can leave your question here for others to answer.
You may also be able to help others by answering some of the questions on the site.
|
Question |
| Asked by: |
Glenn Hawkins |
| Subject: |
germane subject |
| Question: |
I will try to make this inescapably simple.
If you flip a coin on a table it will rotate on its end. If you put a shaft through its center the shaft will rotate with the coin. If you place your finger in front of the shaft, the shaft will apply force against your finger and the coin will be flung away.
When a rotating flywheel that has no shaft and is dropped in a curve, the same curve as if it had a shaft mounted on a pedestal; it attempts to spin like a coin flipped on a table. That is, it attempts to revolve around its center of mass and does not attempt to precess around an outside empty point in space, much as appears though falsely to happen by a gyroscope on a string.
To me this means an object such as a pedestal is necessary to furnish resistance in order for the gyroscope to push against it with an opposite force. This test has been done and it does not prove whether the opposite force is equal, only that some amount of resistance is essential.
I have some logic and uncertain postulations that lead to the belief that with the correct mechanical manipulations of which I am aware of, torque in the flywheel may become stronger than the resistance at the pedestal. If so that would make I. P. possible.
|
| Date: |
6 April 2014
|
| report abuse
|
|
Answers (Ordered by Date)
|
| |
No answers yet |
| Add an Answer >> |
|
